There will be some current, but nothing harmful. If the PE would go all of it's length along the corresponding L and N through the "fuse box" till the point where they are connected together (usually at the connection to the distribution cable), the voltage would be minimum. However the voltage range the digital interface may tolerate (to work with) is just +/-2V including very fast transients, without good GND connection in the cable that will be exceeded really easily.
By the way you have depicted the current path just from the connection between the ballast and lamp, but way higher capacitance is between the arc and ground (the same capacitance responsible for an easy lamp ignition), just because of the rather large lamp surface diameter. You should not forget the arc starts to build up from the hot end, so just before ignition the complete tube becomes one large conductor connected to the hot end, being discharged once the plasma reaches the cold end...
But still these currents are rather low compare to e.g. real hard short circuit fault currents (kA range). And these should be handled by the mains wiring plus signal cables as well (probably the signal disturbance could be tolerated in that case, but it should still not damage the interface; and that limit is in the 5V range, so no more than 5x the operating range; so if 5kA in the PE should not damage it, 1kA won't even disturb the signal, while the lamp won't generate more than 1A peak)
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