The lowest voltage I have seen on a 4ft T12 tube is 71V, and that is from a 63W F48T12HO, presumably due to it's current being doubled. A close second is of course the 79V F34T12 energy saving version of F40T12, and that voltage drop is due to there being some krypton in there. Normal F40T12s are around 101V. So that got me thinking.
- Moving from .43A to .8A results in a ~30% decrease in lamp voltage.
- Moving from pure argon + mercury to a specific mixture of argon + krypton + mercury results in a ~22% decrease in lamp voltage.
What if we do both? Meaning have a lamp that is running at around .8A with a krypton+argon fill. I am sure it doesn't work this way, but if we use those same percentages we get 101*.7=71, 71*(79/101)=55.3V. So A 4ft T12 tube with a drop of ~55V. This is almost certainly low enough to be used with a choke on 120V. And what's more is that 55.3V*.8A=44.24VA, so it's wattage (and hopefully light output) is probably very similar to a normal F40T12, just higher current and lower voltage.
And what's more is that these specs are similar to the 37W F24T12HO (41V@.8A), so there might be compatibility there, no need for dedicated new ballast. If not, there is the possibility of using a 35W HPS choke ballast in a preheat configuration (55V@.83A).
Has anything like this been done before? Meaning two fluorescent lamps of identical physical dimensions and similar wattages that aren't electrically compatible? How possible would this lamp be? This seems like something American Fluorescent would've jumped on with their weird preheat-ish shop lights...
I would make a drawing out of this as usual, but there would probably be nothing visually different about it so that wouldn't be so productive.